Optimal. Leaf size=63 \[ \frac {5 a^3 x}{2}-\frac {4 a^3 \cos (e+f x)}{f}+\frac {a^3 \cos ^3(e+f x)}{3 f}-\frac {3 a^3 \cos (e+f x) \sin (e+f x)}{2 f} \]
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Rubi [A]
time = 0.04, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 5, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {2724, 2718,
2715, 8, 2713} \begin {gather*} \frac {a^3 \cos ^3(e+f x)}{3 f}-\frac {4 a^3 \cos (e+f x)}{f}-\frac {3 a^3 \sin (e+f x) \cos (e+f x)}{2 f}+\frac {5 a^3 x}{2} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 2713
Rule 2715
Rule 2718
Rule 2724
Rubi steps
\begin {align*} \int (a+a \sin (e+f x))^3 \, dx &=\int \left (a^3+3 a^3 \sin (e+f x)+3 a^3 \sin ^2(e+f x)+a^3 \sin ^3(e+f x)\right ) \, dx\\ &=a^3 x+a^3 \int \sin ^3(e+f x) \, dx+\left (3 a^3\right ) \int \sin (e+f x) \, dx+\left (3 a^3\right ) \int \sin ^2(e+f x) \, dx\\ &=a^3 x-\frac {3 a^3 \cos (e+f x)}{f}-\frac {3 a^3 \cos (e+f x) \sin (e+f x)}{2 f}+\frac {1}{2} \left (3 a^3\right ) \int 1 \, dx-\frac {a^3 \text {Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (e+f x)\right )}{f}\\ &=\frac {5 a^3 x}{2}-\frac {4 a^3 \cos (e+f x)}{f}+\frac {a^3 \cos ^3(e+f x)}{3 f}-\frac {3 a^3 \cos (e+f x) \sin (e+f x)}{2 f}\\ \end {align*}
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Mathematica [A]
time = 0.22, size = 44, normalized size = 0.70 \begin {gather*} \frac {a^3 (30 e+30 f x-45 \cos (e+f x)+\cos (3 (e+f x))-9 \sin (2 (e+f x)))}{12 f} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.23, size = 74, normalized size = 1.17
method | result | size |
risch | \(\frac {5 a^{3} x}{2}-\frac {15 a^{3} \cos \left (f x +e \right )}{4 f}+\frac {a^{3} \cos \left (3 f x +3 e \right )}{12 f}-\frac {3 a^{3} \sin \left (2 f x +2 e \right )}{4 f}\) | \(56\) |
derivativedivides | \(\frac {-\frac {a^{3} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+3 a^{3} \left (-\frac {\cos \left (f x +e \right ) \sin \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-3 a^{3} \cos \left (f x +e \right )+a^{3} \left (f x +e \right )}{f}\) | \(74\) |
default | \(\frac {-\frac {a^{3} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+3 a^{3} \left (-\frac {\cos \left (f x +e \right ) \sin \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-3 a^{3} \cos \left (f x +e \right )+a^{3} \left (f x +e \right )}{f}\) | \(74\) |
norman | \(\frac {\frac {5 a^{3} x}{2}-\frac {22 a^{3}}{3 f}-\frac {3 a^{3} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{f}+\frac {3 a^{3} \left (\tan ^{5}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {15 a^{3} x \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}+\frac {15 a^{3} x \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}+\frac {5 a^{3} x \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}-\frac {6 a^{3} \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}-\frac {16 a^{3} \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{3}}\) | \(157\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.35, size = 77, normalized size = 1.22 \begin {gather*} a^{3} x + \frac {{\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a^{3}}{3 \, f} + \frac {3 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{3}}{4 \, f} - \frac {3 \, a^{3} \cos \left (f x + e\right )}{f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.34, size = 58, normalized size = 0.92 \begin {gather*} \frac {2 \, a^{3} \cos \left (f x + e\right )^{3} + 15 \, a^{3} f x - 9 \, a^{3} \cos \left (f x + e\right ) \sin \left (f x + e\right ) - 24 \, a^{3} \cos \left (f x + e\right )}{6 \, f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 121 vs.
\(2 (58) = 116\).
time = 0.15, size = 121, normalized size = 1.92 \begin {gather*} \begin {cases} \frac {3 a^{3} x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {3 a^{3} x \cos ^{2}{\left (e + f x \right )}}{2} + a^{3} x - \frac {a^{3} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {3 a^{3} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} - \frac {2 a^{3} \cos ^{3}{\left (e + f x \right )}}{3 f} - \frac {3 a^{3} \cos {\left (e + f x \right )}}{f} & \text {for}\: f \neq 0 \\x \left (a \sin {\left (e \right )} + a\right )^{3} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.44, size = 58, normalized size = 0.92 \begin {gather*} \frac {5}{2} \, a^{3} x + \frac {a^{3} \cos \left (3 \, f x + 3 \, e\right )}{12 \, f} - \frac {15 \, a^{3} \cos \left (f x + e\right )}{4 \, f} - \frac {3 \, a^{3} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 9.12, size = 156, normalized size = 2.48 \begin {gather*} \frac {5\,a^3\,x}{2}-\frac {\frac {5\,a^3\,\left (e+f\,x\right )}{2}-3\,a^3\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5-\frac {a^3\,\left (15\,e+15\,f\,x-44\right )}{6}+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left (\frac {15\,a^3\,\left (e+f\,x\right )}{2}-\frac {a^3\,\left (45\,e+45\,f\,x-36\right )}{6}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (\frac {15\,a^3\,\left (e+f\,x\right )}{2}-\frac {a^3\,\left (45\,e+45\,f\,x-96\right )}{6}\right )+3\,a^3\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}{f\,{\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+1\right )}^3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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